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Divide 270 in the ratio 3:2:1

As you can see from the question there are 6 parts that 270 needs to be divided by. One sixth of 270 is equal to 45 and so one of the parts is equal to 45. To get the ratio, you have to simply multiply the a...
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Answered by Sinat L. • Maths tutor
37845 Views

A curve C has equation y=(2x-3)^5. Find the equation of the normal of this curve at point P with y coordinate -32.

Finding normals and tangents to curves is a very common question in A-level maths papers, especially core 3 modules, giving between 5-8 marks depending on complexity. In order to start this question, the x c...
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Answered by Natalie C. • Maths tutor
11282 Views

Solve the simultaneous equation- 2x+8y=10 and 3x+2y=5

Firstly, lets name each equation A and B- this will help us later. If I told you what x was, you would be able to use either equation to find y- easy! so lets first find one unknown (x or y) then use that to...
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Answered by Max G. • Maths tutor
6363 Views

How do you differentiate (2x+xe^6x)/(9x-(2x^2)-ln(x)) w.r.t. x?

This problem requires using the quotient rule, product rule and the chain rule. The derivative of the entire thing is ((du/dx)v-(dv/dx)u)/v^2 where u=2x+xe^6x and v=9x-2x^2-lnx. dv/dx is relatively straitfor...
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Answered by Seth H. • Maths tutor
3802 Views

Solve for X and Y: 2y + x = 7; 3y - x = 8

x=1, y=3; Firstly, rearranging for x in the first equation: x = (7-2y); Substitute this into the second equation: 3y - (7 -2y) = 8; Expand: 3y -7 +2y = 8 (watch negative) 3y +2y = 15 Therefore, 5y = 15 and y...
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Answered by Ruth K. • Maths tutor
5854 Views