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This is an integral many people struggle with, but, with a simple trick it becomes a little more straight forward. We will approach this integral using integration by parts. But what are the parts? Well, we ...

This will use the process of integration by parts. First, notice that ln(x)=ln(x)*1. So, the integral of ln(x) is the integral of ln(x) 1. The process of integration by parts is; int (v du / dx ) dx =vu - in...

Take any quadratic equation, eg/ 3x 2 +4x-2=5 , and rearrange to equal 0 , ie/ 3x 2 +4x-7=0 (if you have an expression, ie/ there is no equals sign, then simply equate the expression to 0 ). Now, we use the ...

This problem is all about using integration by parts, so let's start by quoting the formula for integration by parts: ∫u*(dv/dx)dx = uv - ∫v*(du/dx)dx To get the integral we want on the left hand side we can...

For any right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is the sum of the square of the remaining two sides.