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How do you solve inequalities when they involve quadratics? i.e x^2+x-6<0

It is easiest to first solve the quadratic as if it isn't an inequality. This will then help us to sketch the graph of the function which will in turn help us to solve the inequality. So let's change the &lt...
JM
Answered by Jake M. Maths tutor
4505 Views

expand the brackets: (x+3)(x+2)

(x+3)(x+2)we need to multiply each term by both terms in the other bracketFOIL helps us remember the process. First, Outer, Inner, Last so we don't forget any of them.Fist - in this case multiply the first x...
LW
Answered by Luke W. Maths tutor
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Expand the following (x+4)(x+2)

The most important thing to remember when expanding brackets is to make sure that all terms in the one brackets have been multiplied with all the terms in the other.In this case we have two terms in each bra...
JG
Answered by James G. Maths tutor
5284 Views

Differentiate 2e^(3x^2+6x)

Subsitute in u = 3x^2 + 6x and use chain rule to get dy/dx = dx/du x dy/dx to get dy/dx = 2(6x+6)e^(3x^2 +6)
NC
Answered by Nasser C. Maths tutor
4546 Views

Given that the binomial expansion of (1+kx)^n begins 1+8x+16x^2+... a) find k and n b) for what x is this expansion valid?

a) We compare the expansion given to the standard binomial expansion (remembering the powers of k).(1+kx) n =1+n(kx)+(n(n-1)/2)(kx) 2 +...As this is true for all x (for which the expansion holds), we can com...
GC
Answered by George C. Maths tutor
5964 Views