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Factorise fully 2x^2 -x -4=2 and thus solve for x

Recall that to solve a quadratic it needs to be in the form ax 2 + bx +c = 0, Subtract 2 from each side to get 2x 2 -x-6=0 therefore a=2 b=-1 and c=-6 Solve by considering factors c and a that expand out to ...
LS
Answered by Lucy S. Maths tutor
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A = {multiples of 5 between 14 and 26}. B = {odd numbers between 14 and 26}. List the members of A∪B and A∩B.

First write down explicitly what the elements of A and B are.A={15,20,25}, B={15,17,19,21,23,25}. Remember ∪ means OR. So A ∪ B is the set of items which are in either A OR B. This is {15,17,19,21,23,25,15,2...
LP
Answered by Luke P. Maths tutor
16491 Views

∫2x(x+2)^(1/2) dx evaluated from 0->2

First make a substitution so we can apply the power rule ∫x n dx = (x n+1 )/(n+1) + C more simply. Can see u=x+2 means (x+2) 1/2 -> u 1/2 and so will help us apply this rule. Change dx/du=1 implies dx = d...
LP
Answered by Luke P. Maths tutor
13616 Views

Please expand the following brackets: (x+3)(x+5). Give your answer in its simplest form.

So how I would start to solve this problem is by using a method called the claw method (because it looks like a claw).So in order to expand the brackets, we need to multiply each term in the first bracket by...
CL
Answered by Clarence L. Maths tutor
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What is a common factor?

A factor is a number that can be multiplied into another number with nothing left over. The factors of 9 are 1, 3, 9.A common factor is a number that is a factor of two different numbers. The factors of 9 ar...
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Answered by Tom H. Maths tutor
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