Factorise fully 2x^2 -x -4=2 and thus solve for x
Recall that to solve a quadratic it needs to be in the form ax2 + bx +c = 0, Subtract 2 from each side to get 2x2-x-6=0 therefore a=2 b=-1 and c=-6 Solve by considering factors c and a that expand out to equal b: 2 is a prime number and so must have 2 and 1 as the x coefficients and c can have factors -6&1 , -1&6, -3&2 and -2&3Use these to determine which combination expand to give b2x multiplied by -2 gives -4x and x multiplied by 3 is 3x which when added together gives -x which is what we want
Therefore the answer is (2x+3)(x-2)=0 therefore either bracket must equal 0 and so x=-3/2 or x=2
LS
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