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Given that, dy/dx = 6x^2 - 3x + 4, and y = 14 when x = 2, express y in terms of x.

dy/dx = 6x 2 - 3x + 4 To retrieve the original function y from dy/dx you have to integrate the derivative with respect to x. y = ∫(dy/dx)dxy = ∫(6x 2 - 3x + 4)dx To integrate, the power is raised by one and ...
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Answered by Ciaran B. • Maths tutor
6329 Views

Do the circles with equations x^2 -2x + y^2 - 2y=7 and x^2 -10x + y^2 -8y=-37 touch and if so, in what way (tangent to each other? two point of intersection?)

We must first complete the square for both equations and get the equations in the (x-a) 2 +(y-b) 2 =r 2 with the primary objective of determining the centres of both circles (a,b) . Through completing the sq...
SS
Answered by Shanti S. • Maths tutor
4174 Views

Factorise x^2 - 6x + 9 = 0

x 2 - 6x + 9The method for factorising quadratics is to find 2 numbers that add to make the 'x' term (-6x in this case), and multiply together to make the final term (+9 in this case). Factors of +9 are: 1x9...
KB
Answered by Kate B. • Maths tutor
10296 Views

What is 64^1/2 equal to?

A number to the power of 1/2 is the same as square rooting ( √) the number, therefore 64 1/2 is equal to √64. Remember that it can be the positive or the negative square roots, so it could be 8 2 or -8 2 .
KB
Answered by Kate B. • Maths tutor
29902 Views

Differentiate f(x)= 3y^2 + ln (x) + sin x

We have derivative rules. Some of them involve:If f(x)= (x) a => f'(x)= a*x a-1 If f(x)= ln x=> f'(x)= 1/xIf f(x)= sin x=> f'(x)=cos xTherefore, f(x)= 6y+1/x+cos x
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Answered by Daria C. • Maths tutor
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