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dy/dx = 6x^2 - 3x + 4 when y=14 x=2 Find y in terms of x

∫dy/dx = ∫6x^2 - 3x + 4y = (6/3)x^3 - ( 3/2)x^2 + 4x + cLet y = 14 and x = 214 = 2(2^3) - (3/2)(x^2) + 4(2) + c14 = 2(8) - (3/2)(4) + 4(2) + c14 = 16 - 6 + 8 + c14 = 18 + cc = -4therefore:y = 2x^3 - (3/2)x^2...
LA
Answered by Lauren A. • Maths tutor
2583 Views

With a bag of 5 blue marbles, 7 green marbles, and 3 red marbles. What is the probability of picking out two blue marbles? Pick them one at a time and do not replace them.

So there are 15 marbles in total (5 + 7 + 3) The probability of the first marble will be the number of blue marbles / total number of marblesTherefore, you do 5/15 = 1/3 Then for the second marble you do the...
CB
Answered by Christopher B. • Maths tutor
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How do I solve the simultaneous equations 2x - y = 3 and 3x + y = 9

First of all you need to spot a way we can add or subtract these two equations together so that we can get rid of one of the terms . This is easily spotted by writing the equations like so:2x - y = 13x + y =...
JB
Answered by Joshua B. • Maths tutor
6372 Views

How do you factorise a quadratic expression using the formula

To factorise an expression of the formax 2 +bx+c We use the formulaX=(-b+/- (b^2-4ac)^(1/2))/2aExample:Factorise 3X 2 +2X+-1So here a=3 b=2 c=-1From the formula we get X=1/3 and X=-1And so our factorisation ...
KS
Answered by Kaitrin S. • Maths tutor
3449 Views

solve for x, in the form x = loga/logb for 2^(4x - 1) = 3^(5-2x) (taken from OCR June 2014 C2)

We can take logs of both sides straight away, and using the log rule that alogb = log(b^a)So(4x-1) log(2) = (5 - 2x) log(3)We can expand the bracketsso (4x)log(2) - log(2) = 5log(3) - 2xlog(3)We can group th...
EN
Answered by Ellie N. • Maths tutor
9408 Views