dy/dx = 6x^2 - 3x + 4 when y=14 x=2 Find y in terms of x

 ∫dy/dx = ∫6x^2 - 3x + 4y = (6/3)x^3 - ( 3/2)x^2 + 4x + cLet y = 14 and x = 214 = 2(2^3) - (3/2)(x^2) + 4(2) + c14 = 2(8) - (3/2)(4) + 4(2) + c14 = 16 - 6 + 8 + c14 = 18 + cc = -4therefore:y = 2x^3 - (3/2)x^2 + 4x - 4