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Line Q goes through (0,5) and (4,7). Find the equation of Line Q in the form y = mx + c

M = Gradient M = (y 2 - y1)/(x2 - x 1 ) C = the 'y' intercept, where x = 0 Therefore, M = 2/4 = 1/2 = 0.5 y = 0.5x + 5
TD
Answered by Tutor105540 D. • Maths tutor
5322 Views

PQRS is a parallelogram with P->Q=a and P->S=b. Find S->Q in terms of a and b. N is a point between S and Q, where SN:NQ is 3:2, find N->R

Vectors are special in that they have a direction as well as magnitude (size). To get from S->Q you can go from S->P = -b and then P->Q = a so S->Q = - b + a = a - b (remember underlining) To fin...
KB
Answered by Kristian B. • Maths tutor
6170 Views

How can I draw a 30 degree angle without a protractor?

In the exam you will have a ruler and a pair of compasses, which you can use to construct a 60 degree angle by drawing two arcs. You can then draw two more arcs to bisect that 60 degree angle and make a 30 d...
ZC
Answered by Zoe C. • Maths tutor
24680 Views

SOLVE THE FOLLOWING SIMULTANEOUS EQUATIONS: 5x^2 + 3x - 3y = 4, -4x - 6y + 5x^2 = -7

Question: 5x 2 + 3x - 3y = 4, -4x - 6y + 5x 2 = -7.........Step 1: make the y-coefficient equal in both equarions: (y and not x because it has the lowest power so it is easier, but x would also work)...........
AM
Answered by Alonso M. • Maths tutor
7295 Views

Use integration by parts to integrate ∫ xlnx dx

∫ u(dv/dx) dx = uv − ∫ v(du /dx)dx is the Integration by Parts formula. If you set u=lnx, differentiation (rememeber from tables) leads to du/dx= 1/x, and dv/dx=x and so v=x^2/2 (raise power by one then divi...
MM
Answered by Minty M. • Maths tutor
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