Top answers

Solve the equation (3x + 2)/(x - 1) + 3 = 4 (3 marks)

First, multiply all terms by (x - 1) to remove the quotient, and multiply out of the brackets: 3x + 2 + 3(x - 1) = 4(x - 1) >>> 3x + 2 + 3x - 3 = 4x - 4. Next, group all like terms on either side an...
DP
Answered by Daniel P. • Maths tutor
4509 Views

y = 3x^2 + 2x^(1/2) - 12 Find dy/dx

Firstly we divide up the equations into its three compenents based on the powers of the x values, giving us 3x^2, 2x^(1/2) and -12. Now one at a time, we multiply the coefficient by the power of x, and then ...
SR
Answered by Sam R. • Maths tutor
6224 Views

Solving 2tan(x) - 3sin(x) = 0 for -pi ≤ x < pi

The first step to answering this question is to get the equation in a simpler form. Aim to have it solely in terms of sin(x) and cos(x) with no fractional parts. To begin doing this, remember that tan(x) = s...
BA
Answered by Benjamin A. • Maths tutor
21918 Views

Take the polynomial p(x)=x^4+x^3+2x^2+4x-8, use the factor theorem to write p(x) as two linear factors and an irreducible quadratic. An irreducible quadratic is a quadratic that can not be factorised.

We must use the factor theorem since that is what the question asks. So we take p(x) and think about the factors of 8 we then evaluate it at x=1 to start, then move onto x=-1,2,-2 and so on. We see that it h...
JC
Answered by Jordan C. • Maths tutor
4650 Views

How would the integral ∫x^2sin2xdx be solved using integration by parts?

The general formula for integration by parts is given as ∫u(dv/dx)dx = uv - ∫v(du/dx)dx given that the equation to be solved is ∫x 2 sin2xdx, the values for u, v, du/dx and dv/dx can be assigned as u = x 2 d...
SN
Answered by Samuel N. • Maths tutor
11483 Views