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You would start with this equation (x – a) 2 + (y – b) 2 = r 2 , with the center being at the point (a, b) and the radius being "r". Therefore you would have (x-2) 2 +(y+1) 2 =r 2 , in order to det...

times the whole equation by the denominator of the left fraction giving p(2q+4)(p+1) - (qp(p+1))/p notice that p can be cancelled in the right fraction, and then times out to give 2qp^2 + 4p + 4p^2 + 2pq - q...

Ok so there are two basic steps to integrating a function: You add 1 to the power of any x term. e.g. x 2 -> x 3 , 2x 7 -> 2x 8 , 3 = 3x 0 -> 3x You divide the term by the new power e.g. if the new ...

First, we need to write cos 2 x in a form that is easily integrable. We can use the double angle formula cos(2x) = 2cos 2 x - 1 to see that cos 2 x = 1/2cos(2x)+1/2. Now, we can integrate the terms seperatel...

Often, substitution is used when dealing with quadratic simultaneous equations as the other method, elimination, is more straightforward and can be used to solve linear equations but it cannot be used for qu...