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(4x + 3)/(x + 1) + 2 = 8

(4x + 3)/(x + 1) + 2 = 8 Firstly minus the 2 from both sides (4x + 3)/(x + 1) = 6 Then multiply both sides by the denominator (x + 1) 4x + 3 = 6(x + 1) Expand the brackets. 4x + 3 = 6x + 6 Rearrange the equa...
JW
Answered by Jessica W. • Maths tutor
3463 Views

Circle C has equation x^2 + y^2 - 6x + 4y = 12, what is the radius and centre of the circle

The equation of a circle is (x-a)^2 + (y-b)^2 = r^2, where (a,b) is the centre of the circle, and r is the radius. To condense our equation into this form we have to use the technique of completing the squar...
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Answered by Haren B. • Maths tutor
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Solve these pair of simultaneous questions: 3x+2y=17 4x-y=30

Let's solve for x first by substituting y in terms of x. 4x-y=30 y=4x-30 3x+2y=3x+2(4x-30)=3x+8x-60=11x-60 11x-60=17 11x=77 x=7 Now let's solve for y by substituting x for 7 3x +2y=17 3(7)+2y=17 21+2y=17 2y=...
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Answered by Jin-Ho Y. • Maths tutor
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When finding the turning points of a curve, how can I tell if it is a maximum, minimum or a point of inflection?

To find the turning points of a curve one must find the values of x which satisfy dy/dx = 0. To further determine what type of turning point this is you need to compute the second derivative with respect to ...
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Answered by Ben S. • Maths tutor
11388 Views

Solve the simultaneous equations. x^2 + y^2 = 29. y-x = 3

The 2 equations are: 1) x 2 + y 2 = 29 2) y-x=3 In this kind of simultaneous equation, you cannot take it away from each other. Instead, you need to substitue. To do so, rearrange the 2nd equation to make x ...
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Answered by Pallave S. • Maths tutor
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