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Solve x(x-1)-12=0

Expand the brackets to find x 2 -x-12=0Factorise the equation to find (x-4)(x+3)=0Check it expands to equal x 2 -x-12=0Find the value of x as:x+4=0 therefore X=4x-3=0 therefore X=-3
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Answered by Sarah W. • Maths tutor
3139 Views

Factorise fully X^2 - 6X + 8

Factorising means reducing an equation to a set of brackets, in the form (x+a)(x+b), where a and b are constants. To factorise this equation, we must find two numbers that add to make -6, and multiply to mak...
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Answered by Dan D. • Maths tutor
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Solve the following equation: x^2- x - 12 = 0

When looking at this equation, we need to think of two numbers that multiply together to give 12 and have a difference of one. We can rewrite the equation as the following: (x-4)(x+3) = 0 Solving for x:This ...
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Answered by Daniel L. • Maths tutor
3063 Views

3/(x-1) - 2/(x+1) = 1 Solve to find the values of x.

3(x+1) - 2(x-1) = 1(x-1)(x+1)3x + 3 - 2x + 2 = x 2 - 1x 2 - x - 6 = 0(x - 3)(x + 2) = 0x = 3 x = -2
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Answered by Ece B. • Maths tutor
3305 Views

You are given two equations: 3y-2x=11 and y+x=12. By solving simultaneously, what is the value of x and the value of y.

Begin by setting up the equations simultaneously. To make it easier we can label the equations (1) and (2)3y-2x=11 (1)y+x=12 (2)We then need to make the values of y or the values of x equal in both equations...
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Answered by Natasha F. • Maths tutor
3731 Views