You are given two equations: 3y-2x=11 and y+x=12. By solving simultaneously, what is the value of x and the value of y.

Begin by setting up the equations simultaneously. To make it easier we can label the equations (1) and (2)3y-2x=11 (1)y+x=12 (2)We then need to make the values of y or the values of x equal in both equations and we can do this through multiplication. So if we make the values of y equal, we need to times equation (2) by 3. Remember to multiply the whole equation by 3.3y-2x=113y+3x=36We can then minus the two equations to cancel out the 3y.-5x=-25Then divide both sides by -5 to give x=5. We then substitute this value back into one of the equations. I am going to substitute it back into equation (2).y+5=12Take away 5 from both sides and y =7Therefore the answer is x=5 and y=7. We can check this answer by substituting the values into equation 1.3(7)-2(5)=11

NF
Answered by Natasha F. Maths tutor

3286 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify the following: 2(3-2x) - 3(x+1)


A washing machine costs £500 in a sale and was reduced by 20%. What was its original price?


A farmer has 30 boxes of eggs. There are 6 eggs in each box. Write, as a ratio, the number of eggs in two boxes to the total number of eggs. Give your answer in its simplest form.


PQRS is a parallelogram with P->Q=a and P->S=b. Find S->Q in terms of a and b. N is a point between S and Q, where SN:NQ is 3:2, find N->R


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning