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find the integral of f'(x)=2x+5

f'(x)=2x+5 note that f'(x)=nx n-1 so 2x is originally x 2 as this is 2x 2-1 and 5 is originally 5x 1-1 f(x)= x 2 +5x+c the c is a constant which means it's any real number without an x to it as 0 is ...
ZS
Answered by Zivanayi S. • Maths tutor
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How do you factorize a quadratic equation which has a coefficient of x^2 other than 1?

Factorise 6x 2 + x - 2 = 0 Firstly, multiply the coefficient of x 2 by the last number: 6 x -2 = -12 List all the factors of 12 and see which pair adds/subtracts to make 1: Factors of 12: [1,12] [2,6] [3,4] ...
AA
Answered by Aleezeh A. • Maths tutor
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Express the polynomial x^3+x^2-14x-24 as a product of three linear factors.

Firstly, use the factor theorem to determine one factor. Substitute factors of 24 into the equation, beginning at plus or minus 1 and then increasing. The first factor found will be -2, therefore (x+2) is a ...
SW
Answered by Scarlet W. • Maths tutor
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Kenny has £3200 in a savings account. After a year, the bank pays him interest increasing his balance to £3360. What percentage rate was applied to the account?

Kenny originally had £3200 After a year, he had £3360 £3360 - £3200 = £160 160/3200 = 0.05 0.05 x 100 = 5% Therefore, a 5% interest rate was applied to Kenny's account
MC
Answered by Megan C. • Maths tutor
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Solve the quadratic equation x^2 - 5x - 14 = 0, using factorisation.

Using factorisation, first we would have to look at the factors that multiply to make the last term, (-14). We know that they are +/- 7 and -/+2, and +/- 14 and -/+ 1, respectively. Now we have listed the fa...
ME
Answered by Mram E. • Maths tutor
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