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The curve C has equation 2x^2y+2x+4y-cos(pi*y)=17 A) Use implict differenciation to find dy/dx B) point P(3,0.5) lies on C, find the x coodinate of the point A at which the normal to C at P meets the x axis.

A) dy/dx = (-4xy-2) / (2x 2 +4+pi sin(pi y) B) (62+3*pi) / (22+pi)
AH
Answered by Alisha H. • Maths tutor
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y=x^2, find dy/dx

y=x^2 if y = a*x^b then dy/dx = ba*x^(b-1) therefore dy/dx = 2*x
MW
Answered by Matthew W. • Maths tutor
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Simplify (x + 3)(2x + 5) - (x - 1)

Start by expanding the brackets: 2x^2 + 5x + 6x + 15 = 2x^2 +11x + 15 Combine the two parts of the equation: 2x^2 + 11x + 15 - x + 2 = 2x^2 + 10x + 17
HM
Answered by Hannah M. • Maths tutor
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Fully simplify: (y^2 x y^5) / y^3

(y 2 x y 5 ) / y 3 When multiplying, the indices must be added together, therefore y 2 x y 5 = y 2+5 = y 7 (y 2 x y 5 ) / y 3 = y 7 / y 3 When dividing, the indices must be subtracted, numerator from denomin...
JP
Answered by Jemima P. • Maths tutor
5864 Views

Increase £160 by 45%.

If £160 = 100%, the number we are trying to find (let's call this X) equals 145%. (Place numbers in 2x2 grid) 100% £160 145% X Multiply the two diagonal numbers together, then divide by the number opposite X...
JP
Answered by Jemima P. • Maths tutor
5060 Views