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Can you solve 18-7x < 12-3x ?

In order to solve this formula, you would need to collect similar terms to the same side and then simplify to work out the value of 'x'. We can do this by collecting all the 'x' terms to one side first, trea...
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Answered by Blessing F. Maths tutor
4180 Views

Find the equation of a straight line that passes through the coordinates (12,-10) and (5,4). Leaving your answer in the form y = mx + c

Finding the gradient (m): The gradient is the change in y-axis over the change in x-axis Δy = -10-4= -14 Δx = 12-5=7 Δy/Δx = -14/7 = -2 Accumilating the equation: The equation of a straight line can be deduc...
MM
Answered by Martin M. Maths tutor
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The polynomial f(x) is define by f(x) = 3x^3 + 2x^2 - 8x + 4. Evaluate f(2).

f(x) = 3x^3 + 2x^2 - 8x + 4 f(2) = 3(2)^3 + 2(2)^2 - 8(2) + 4 f(2) = 3(8) + 2(4) - 8(2) + 4 f(2) = 24 + 8 - 16 +4 f(2) = 20
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Answered by Sophie W. Maths tutor
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If y = 2/3 x^3 + x^2; a) What is dy/dx? b) Where are the turning points? c) What are the nature of the turning points?

a) By simple parametric differentiation of each term, dy/dx = 2x^2 + 2x b) The condition for a turning point is the gradient (dy/dx) at that point is zero. 0 = x(2x + 2) so either x=0 or 2x+2=0. Therefore th...
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Answered by Annabel F. Maths tutor
5004 Views

Integrate x*sin(x) with respect to x.

We integrate by parts: u=x u'=1; v'=sin(x) v=-cos(x) integral(x sin(x)dx) = -x cos(x) + integral(cos(x)dx) = -x*cos(x) + sin(x) + C where C is a constant.
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Answered by James R. Maths tutor
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