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The line AB has equation 3x + 5y = 7, find; a) the gradient of AB b) the x-axis and y-axis intercepts c) sketch the graph

a) Rearrange equation into the form y = mx + c where m is the gradient and c is the y-axis intercept. Gradient AB = -3/5. b) The y-intercept is c which = 7/5. To find x-axis intercept we set y=0 and rearrang...
WH
Answered by Will H. • Maths tutor
5481 Views

Solve the following quadratic equation: x^2 + 3x + 2 = 0

Step 1: Find factors of the constant (The number with no x attached to it), In our case this is 2. The factors of 2 are: 1 & 2 and -1 & -2. Step 2: The sum of the factors from step 1 must equal the n...
JS
Answered by Jack S. • Maths tutor
4760 Views

Solve for x: 2x^2 + 2x -24 = 0

The general formula of a quadratic is ax^2 + bx + c -> this is a quadratic 2) Factorise using common factor (=2) -> 2(x^2 + x - 12) = 0 3) Factorise the quadratic to (x + m)(x + n): the two numbers (m ...
YZ
Answered by Yige Z. • Maths tutor
11531 Views

Simplify: (3x+8)/5 > 2x + 1

Multiply both sides by 5: 3x + 8 > 10 x + 5 Move 3x to RHS by subtracting 3x from both sides: 8 > 7x + 5 Move 5 to LHS by subtracting 5 from both sides: 3 > 7x Make the coefficient of x equal 1 by d...
OD
Answered by Orlaith D. • Maths tutor
4761 Views

Factorise f(x) = x^2+4x+4 and sketch the curve, identifying the roots and minimum point of f(x).

f(x) = (x+2)(x+2) When f(x) = 0, x = -2. f'(x) = 2x + 4 When f'(x) = 0, x = -2, and corresponds to the minimum point. Therefore, the sketch of the curve will be a U-shaped parabola which touches the x-axis a...
OD
Answered by Orlaith D. • Maths tutor
4289 Views