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Point A (-3,5) and point B (1,-15) are to be connected to form a straight line, fing the equation of the line in the form y=mx+c?

First identify your x1, y1 and x2,y2. It is helpful to write this above the two points A and B. To find the gradient the following equation can be used (I will show equation on board),as u can see the X1, Y1...
CW
Answered by Charuka W. • Maths tutor
6559 Views

The line L has equation y = 5 - 2x. (a) Show that the point P (3, -1) lies on L. (b) Find an equation of the line perpendicular to L that passes through P.

(a) To confirm that point P lies on L, we must substitute x = 3 into the equation and see if we get y = -1. y = 5 - 2(3) = -1, therefore P lies on the line L (b) The gradient of the perpendicular line is -1/...
KS
Answered by Kitty S. • Maths tutor
15115 Views

A gardener uses this formula to work out how much he charges to make a lawn. C = 7(14 +A)/ 3. C is the charge in £. A is the area in m2. He makes a rectangular lawn measuring 12.5 m by 17.6 m. How much does he charge?

Area of lawn = 12.5 x 17.6 = 220 m2 Substituting into the formula given the cost if found, C = 7(14 + 220)/3 = £546
KS
Answered by Kitty S. • Maths tutor
5850 Views

How do I find f'(x) for f(x)=4x^3+x^2+5x+8?

This question require you to differentiate. The general rule for this format of differentiation is to multiply the number in front of the x by the power of the x and then reduce the power by one (in formula ...
NC
Answered by Naomi C. • Maths tutor
23336 Views

Differentiate f(x) with respect to x. Find the stationary value and state if it is a maxima, minima or point of inflection f(x) = 6x^3 + 2x^2 + 1

differentiate 6x^3 + 2x^2 + 1 = 18x^2 + 4x To determine stationary point set second derivative to zero 2nd derivative =36x + 4 36x + 4 = 0 therefore x = -4/36 = -1/9 x is -ve therefore point x = -1/9 is a ma...
HH
Answered by Harry H. • Maths tutor
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