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Find the all the angles of a triangle with side lengths of 8cm, 11cm and 11cm.

Using the knowledge of a 2 = b 2 + c 2 - 2bcCos(A) Rearrange to aquire Cos(A) = (b 2 + c 2 - a 2 )/2bc Then input the values to obtain the angles of 42, 69, 69.
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Answered by Alexander J. Maths tutor
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Differentiate with respect to x: 4(x^3) + 2x

d/dx(4x 3 + 2x) = d/dx (4x 3 ) + d/dx(2x) = 4(3x 2 ) + x = 12x 2 + x
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Answered by Alexander J. Maths tutor
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How do I add up the integers from 1 to 1000 without going insane?

Suppose you are asked by your teacher to sum all the integers from 1 up to 1000. You might be thinking they must hold some kind of grudge against you. If you try to calculate the sum by adding on each intege...
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Answered by Matthew B. Maths tutor
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Differentiate y=(4x - 5)^5 by using the chain rule.

Notation: I use the ^ in the title question to indicated 'to the power of' and I use an asterisk * (or star) to indicate 'multiplied by' in the answer, to avoid confusion with the x term! Step 1) let u = 4x ...
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Answered by Joseph E. Maths tutor
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Finding Roots of Quadratic Equations

Finding Roots of Quadratic Equations What is a root to an equation? A root to an equation is a set of value(s) that satisfy the equation and when shown graphically they are the x values at which the function...
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Answered by Alexander G. Maths tutor
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