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How do I express y=acosx+bsinx in the form y=Rcos(x-c)?

From the addition formula, we know that: Rcos(x-c) = Rcos(x)sin(c)+Rsin(x)cos(c) Therefore: acos(x)+bsin(x) = Rcos(x)cos(c)+Rsin(x)sin(c) If we equate the coefficients of cos(x) and sin(x) we see that: acos(...
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Answered by Daniel R. Maths tutor
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How do I find where the stationary points of a function are?

If you were to draw a graph of the function, a stationary point would be a point on the graph where the gradient is zero, i.e the graph has no vertical slope. For example consider the function f(x) = 2. This...
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Answered by Laasya S. Maths tutor
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How do I differentiate sin^2(x)?

To differentiate this, we must use the Chain Rule . This is because we have two functions multiplied by each other: (x) sin⁡(x). We use the substitution u = sin(x). This is our initial function, and we can s...
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Answered by Laasya S. Maths tutor
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How to find the equation of a tangent to a curve at a specific point.

The first thing to remember is that the tangent to the curve at a given point has the same gradient as the curve at that point. Let's consider the general case y=f(x) at a point c=(x1,y1). Step 1:We have to ...
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Answered by Rafe L. Maths tutor
10911 Views

Integrating cos^2(x)+5sin^2(x)

Firstly, note that cos^2(x)+5sin^2(x)= cos^2(x) +sin^2(x) +4sin^2(x). By trignoemtric identies, cos^2(x)+sin^2(x)=1 and so we can just integrate 1+4sin^2(x) since this is equal to cos^2(x)+5sin^2(x). Again, ...
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Answered by Rafe L. Maths tutor
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