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Differentiate expressions of form Ax^b where A and b are constants and x is a variable

First you have Ax^b where x is a variable. Then you multiply A and b together with the variable so you have Abx^b Then you minus 1 from the b which gives you the final answer Abx^(b-1)
RI
Answered by Rafi I. Maths tutor
5210 Views

How and when do you use integration by parts?

Integration by parts is a method of integration used when you are attempting to integrate a function which is the product of two functions. If the two products can be expanded there is usually an easier way ...
AP
Answered by Ashley P. Maths tutor
8946 Views

How to integrate e^(5x) between the limits 0 and 1.

Note that by the chain rule if the function y is such that y(x)=f(g(x)), where f and g are functions, then the derivative of y wrt x is given by dy/dx = (df/dg)*(dg/dx). Hence if we let the function y be e^(...
MS
Answered by Max S. Maths tutor
12894 Views

What is differentiation and how is it done?

Differentation is a type of calculus that allows us to work out the rate of change. For example, if we have a straight line graph such as y=2x, we know that the gradient of the line is 2. If we take a curve ...
MP
Answered by Megan P. Maths tutor
11783 Views

How do I factorise quadratic equations?

x 2 +x-6=y Is the equation we will use to demonstrate how to factorise quadratics. The first step involves using the basic shape of all quadratic factorisation: ax 2 +bx+c=y x 2 +x-6=y (Cx+A)(Dx+B)=y We must...
JO
Answered by Joshua O. Maths tutor
5223 Views