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Firstly we should notice the similarities between this expression and expressions of the standard type a x. To deal with this type of expression, we take logarithms of both sides and then apply the usual rul...

Factorising quadratic equations This method is used for the following factorable expression: ax 2 +bx+c Although this method is particularly useful with quadratic expressions with a≥2, it can be also used wh...

This is an integral many people struggle with, but, with a simple trick it becomes a little more straight forward. We will approach this integral using integration by parts. But what are the parts? Well, we ...

This will use the process of integration by parts. First, notice that ln(x)=ln(x)*1. So, the integral of ln(x) is the integral of ln(x) 1. The process of integration by parts is; int (v du / dx ) dx =vu - in...

Take any quadratic equation, eg/ 3x 2 +4x-2=5 , and rearrange to equal 0 , ie/ 3x 2 +4x-7=0 (if you have an expression, ie/ there is no equals sign, then simply equate the expression to 0 ). Now, we use the ...