Top answers

In a right-angled triangle calculate the length of the hypotenuse when the side lengths at 5cm and 7cm. Leave your answer as a surd.

Using pythagoras’ theorem:a^2 + b^2 = c^2 hypotenuse = sqrt(5^2 + 7^2) = sqrt(25+49) = sqrt(74)
Answered by • Maths tutor
3704 Views

Solve the equation x^2 + 10x + 24 = 0

So, we are dealing here with a quadratic equation as it is written in the form ax^2 + bx +c = 0 To tackle this we will firstly need to factorise the equation, we need to find two numbers that will multiply t...
AS
Answered by Aleema S. • Maths tutor
3401 Views

A curve C with an equation y = sin(x)/e^(2x) , 0<x<pi has a stationary point at P. Find the coordinates ofP?

Firstly notice that to find a stationary point of a curve with an equation, the best first step is often to differentiate the expression. Then solve the equation for x when dy/dx = 0. In this case the y equa...
RE
Answered by Rufus E. • Maths tutor
6947 Views

Factorise 8x^2 + 6x +1

8x 2 + 6x + 1. This is a quadratic equation as the highest power of x is to the power of 2.A quadratic is written in the form: ax 2 + bx + c. The coefficient of the x 2 term is greater than one. So you need ...
Answered by • Maths tutor
5957 Views

Given that x=3 is a solution to f(x)= 2x^3 - 8x^2 + 7x - 3 = 0, solve f(x)=0 completely.

As x=3 is a solution, (x - 3) is a factor of f(x) = 2x 3 - 8x 2 + 7x - 3 = 0 ie. 2x 3 - 8x 2 + 7x - 3 = (x - 3)(Ax 2 + Bx + C) where A,B,C are constants to be found. Expanding and then grouping terms by powe...
AS
Answered by Adrian S. • Maths tutor
8157 Views