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y=2x+5, calculate x when y=11

So what we need to do is work out what x is when y is equal to 11.Firstly, we would rearrange the equation so that x is the subject and to do this we subtract 5 from both sides.Thisgives us y-5 =2x. Dividing...
DA
Answered by Daniaal A. • Maths tutor
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Express 3x+1/(x+1)(2x+1) in partial fractions

3x+1/(x+1)(2x+1)=A/(x+1) + B/(2x+1)Multiply equation by (x+1) and (2x+1) to get:3x+1= A(2x+1) + B(x+1)Let x=-1 (x+1=0 so x=-1) sub into new equation. -2= A(-1) + B (x+1)-2=-AA=2Let x=-1/2 and sub into same e...
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Answered by Niamh M. • Maths tutor
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Figure 1 shows a sector AOB of a circle with centre O and radius r cm. The angle AOB is θ radians. The area of the sector AOB is 11 cm2 Given that the perimeter of the sector is 4 times the length of the arc AB, find the exact value of r.

theta/2pi x2pi r = length of ABso therefore simplifying gives... theta r = AB Perimeter = 2r+theta requate the answer of 4 AB to the perimeter.Solve for theta which eventually give 2/3then put theta in the e...
TD
Answered by Tutor460124 D. • Maths tutor
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Why can’t you use the quadratic formula for every quadratic?

For most Quadrátics in the form of ax^2+bx+c=0there is atleast 2 solutions in most cases as the graph of the quadratic passes the x axis on most cases. But In some cases the quadratic graph doesn’t Cross the...
CG
Answered by Carlos G. • Maths tutor
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What is the signed area between the curve y = x^2 - 4 and the x-axis?

The curve y = x^2 - 4 is a parabola that crosses the x axis at x = - 2 and x = 2, so the area that we are looking for is the area within the parabola when y <= 0 and -2<= x <= 2. So we expect our ar...
Answered by • Maths tutor
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