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How do you solve linear algebraic equations?

3 simple steps: Expand out brackets. Group like terms together. Make x the subject of the equation.
AP
Answered by Athul P. • Maths tutor
3270 Views

Differentiate with respect to x: x*cos(x)

Firstly, x cos(x) is a product of two functions of x. Therefore we can use the product rule to work out the derivative of the whole function. Differentiating each part makes it easier to visualize the formul...
SS
Answered by Stefan S. • Maths tutor
3631 Views

What is 2 1/5 + 1 3/4

First simplify both sides:2 1/5 = 11/5 1 3/4 = 7/4Then find common denominator by multiplying denominators:4/5 = 20Times denominators by opposite denominator (do to top and bottom):7/4 = 35/20 13/5 = 44/20Th...
HH
Answered by Harry H. • Maths tutor
4160 Views

The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

We know the perimiter is split into the proportions 3:4:5 therefore by adding 3+4+5 we can work out what fraction of 72cm each side is.Thus 3/(3+4+5) = 3/12 = 1/4 is the fraction of 72 that belongs to the sh...
SD
Answered by Sefton d. • Maths tutor
11950 Views

Prove cosec2A-cot2A=tanA

Cosec2A - cot2A= tanA Left hand side=1/sin2A - cos2A/sin2A =(1- cos2A)/sin2A =(1-(1- 2 sin^2⁡ A)/ 2sinAcosA =(1-1 + ( 2 sin^2⁡ A))/ 2sinAcosA =sinA/cosA =tanA Therefore left hand side of the equation is equa...
ST
Answered by Sherin T. • Maths tutor
14054 Views