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HIGHER TIER a) Factorise the following equation into two bracket form: 2x^2-5x-12. b)2x^2-5x-12=0. Solve this equation to find the values of x, using your answer to part a). BONUS c) Sketch the function y=2x^2-5x-12, showing any x intercepts

a) Find two common numbers that ADD UP to give -5, and MULTIPLY TOGETHER to give (2*-12=) -24 MULTIPLY TO -24 -1 and 24 1 and -24 -2 and 12 2 and -12 3 and -8 -3 and 8 4 and -6 - 4 and 6 ADD TO -5 5 and -10 ...
JV
Answered by Jonathan V. • Maths tutor
4317 Views

Solve the equation ((2x+3)/(x-4)) - ((2x-8)/(2x+1)) = 1. Give your answer to 2 decimal places.

Multiply both sides of the equation by the denominators to get:(2x+3)(2x+1) - (2x-8)(x-4) = (x-4)(2x+1)Expand all the brackets to get:(4x^2 + 6x + 2x + 3) - (2x^2-8x-8x+32) = 2x^2-8x+x-4Simplify both sides t...
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Answered by Natalie S. • Maths tutor
3701 Views

Given that f(x)=6x+4 and g(x)=3x^2+7, calculate g of f, for x=2.

First to make it easier you can convert ( g o f)(x) to g (f(x)) so that it is more clear.All you need to do is input function f into the function g in the place of "x - the unknown ".Therefore, sin...
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Answered by Aniela B. • Maths tutor
1939 Views

Given a curve has the equation f'(x) = 18x^2-24x-6 and passes through the point (3,40), use integration to find f(x) giving each answer in its simplest form.

Firstly we need to integrate f(x). The general rule is: the integral of x^n = (1/(n+1))x^(n+1)+CSo apply that rule to each term of f'(x) as so:Integral of 18x^2 = (18/(2+1))x^(2+1) = 6x^3 Integral of -24x = ...
HB
Answered by Henry B. • Maths tutor
3464 Views

What is a box-plot diagram?

(In session I would begin by drawing a box-plot diagram and seeing if a student can also covert their data into a box-plot)There are 5 key points to a box-plot. You have the minimum value, lowest quartile, m...
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Answered by Will W. • Maths tutor
3652 Views