Answers>Maths>IB>Article

Given that f(x)=6x+4 and g(x)=3x^2+7, calculate g of f, for x=2.

First to make it easier you can convert ( g o f)(x) to g (f(x)) so that it is more clear.All you need to do is input function f into the function g in the place of "x - the unknown ".Therefore, since function f(x) is 6x+4, and in function g(x) the unknown is multiplied by 3 and squared,the function( g o f)(x) is equal to 3(6x+4)^2+7to calculate ( g o f)(x) for x=2 we need to substitute 2 for x( g o f)(2)=3(62+4)^2+7first you square the result from the brackets - (62+4)^2=16^2=256now you multiply the squared result by 3 and add 7 - 256*3+7=775Thus ( g o f)(x) for x=2 is 775.

AB
Answered by Aniela B. Maths tutor

1756 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

How to integrate ∫〖3x/√(1-x^2 ) dx〗?


What is a derivative - Introduction to Calculus


Consider the functions f and g where f(x)=3x-5 and g(x)=x-2. (a) Find the inverse function for f. (b) Given that the inverse of g is x+2, find (g-1 o f)(x).


The fifth term of an arithmetic sequence is equal to 6 and the sum of the first 12 terms is 45. Find the first term and the common difference.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning