Answers>Maths>IB>Article

Given that f(x)=6x+4 and g(x)=3x^2+7, calculate g of f, for x=2.

First to make it easier you can convert ( g o f)(x) to g (f(x)) so that it is more clear.All you need to do is input function f into the function g in the place of "x - the unknown ".Therefore, since function f(x) is 6x+4, and in function g(x) the unknown is multiplied by 3 and squared,the function( g o f)(x) is equal to 3(6x+4)^2+7to calculate ( g o f)(x) for x=2 we need to substitute 2 for x( g o f)(2)=3(62+4)^2+7first you square the result from the brackets - (62+4)^2=16^2=256now you multiply the squared result by 3 and add 7 - 256*3+7=775Thus ( g o f)(x) for x=2 is 775.

AB
Answered by Aniela B. Maths tutor

1568 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

Consider f (x) = logk (6x - 3x 2 ), for 0 < x < 2, where k > 0. The equation f (x) = 2 has exactly one solution. What is the value of k?


What is the equation of the tangent drawn to the curve y = x^3 - 2x + 1 at x = 2?


Consider the arithmetic sequence 5,7,9,11, …. Derive a formula for (i) the nth term and (ii) the sum to n terms. (iii) Hence find the sum of the first 20 terms.


How do i solve simultaneous equation with more than two equations and two unknowns?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning