Top answers

The sides of an equilateral triangle are given by the expressions x+y, 2y-1 and 3y-2x+1. Find the values of x and y.

This question test knowledge of the geometry of equilateral triangles and the students ability to solve linear equations. First we note that an equilateral triangle has equal sides. Then we can write that x+...
JS
Answered by Joe S. • Maths tutor
8925 Views

Factorise fully 2x^2 -x -4=2 and thus solve for x

Recall that to solve a quadratic it needs to be in the form ax 2 + bx +c = 0, Subtract 2 from each side to get 2x 2 -x-6=0 therefore a=2 b=-1 and c=-6 Solve by considering factors c and a that expand out to ...
LS
Answered by Lucy S. • Maths tutor
3194 Views

A = {multiples of 5 between 14 and 26}. B = {odd numbers between 14 and 26}. List the members of A∪B and A∩B.

First write down explicitly what the elements of A and B are.A={15,20,25}, B={15,17,19,21,23,25}. Remember ∪ means OR. So A ∪ B is the set of items which are in either A OR B. This is {15,17,19,21,23,25,15,2...
LP
Answered by Luke P. • Maths tutor
16351 Views

∫2x(x+2)^(1/2) dx evaluated from 0->2

First make a substitution so we can apply the power rule ∫x n dx = (x n+1 )/(n+1) + C more simply. Can see u=x+2 means (x+2) 1/2 -> u 1/2 and so will help us apply this rule. Change dx/du=1 implies dx = d...
LP
Answered by Luke P. • Maths tutor
13456 Views

Please expand the following brackets: (x+3)(x+5). Give your answer in its simplest form.

So how I would start to solve this problem is by using a method called the claw method (because it looks like a claw).So in order to expand the brackets, we need to multiply each term in the first bracket by...
CL
Answered by Clarence L. • Maths tutor
4560 Views