Top answers

Expand the brackets: (2m-3)(m+1)

To expand the brackets we consider each bracket separately, (2m-3) which is multiplied by (m+1). Consider first the first identity in each bracket:2m x m = 2m 2 Then consider the first identity and the last ...
HM
Answered by Hannah M. • Maths tutor
6011 Views

Differentiate 4(x^3) + 3x + 2 with respect to x

Solution: 12x 2 + 3 Working: General differentiation formular: d/dx (ax n ) = an(x n-1 ) So we multiply the coefficient (constant infront) of the x term by the power of x (in this case: n) and reduce the pow...
TD
Answered by Tutor77028 D. • Maths tutor
4361 Views

Find the acute angle between the two lines... l1: r = (4, 28, 4) + λ(-1, -5, 1), l2: r = (5, 3, 1) + μ(3, 0, -4)

To do this, we will only consider the direction vectors of each line. That is to say, the vector 'attached' to our λ and μ terms (which are called scalar parameters).We will do this because the angle between...
RB
Answered by Rory B. • Maths tutor
13840 Views

How should I divide up my time during the exam?

Use the number of marks as a guide - if the paper is worth 80 marks and you're given 1.5 hours, I'd allocate 1 minute per mark which would give you 10 minutes (or more if you're quick) to check over your ans...
RR
Answered by Ruth R. • Maths tutor
5965 Views

The point P has coordinates (3,4). The Point Q has the coordinates (a,b). A line perpendicular to PQ is given by the equation 3x+2y=7. Find an expression for b in terms of a.

As we appreciate the rule 1: gradient of line PQ multiplied by the gradient of the line perpendicular to it equals -1. Formula: m x mn=-1We use this to find the gradient of line PQ:Firstly, we find the gradi...
RT
Answered by Richard T. • Maths tutor
7534 Views