Differentiate 4(x^3) + 3x + 2 with respect to x
Solution: 12x2 + 3
Working:
General differentiation formular: d/dx (axn ) = an(xn-1)
So we multiply the coefficient (constant infront) of the x term by the power of x (in this case: n) and reduce the power by 1.
d/dx (4x3 + 3x +2) = d/dx (4x3) + d/dx(3x) + d/dx(2)
= 43x3-1 + 31x1-1 + 0
= 12x2 + 3
Note: for the second term in the expression, x can be written x1 and also x0 = 1. This is true for any value to the power of zero.
Notation: 3*4 = 3 times 4 =12
TD
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