Differentiate 4(x^3) + 3x + 2 with respect to x

Solution: 12x+ 3

Working:

General differentiation formular:  d/dx (ax) = an(xn-1

So we multiply the coefficient (constant infront) of the x term by the power of x (in this case: n) and reduce the power by 1.

d/dx (4x3 + 3x +2) = d/dx (4x3) + d/dx(3x) + d/dx(2)

                              = 43x3-1 + 31x1-1 + 0

                              = 12x2 + 3

Note: for the second term in the expression, x can be written x1 and also x0 = 1. This is true for any value to the power of zero.

Notation: 3*4 = 3 times 4 =12

TD
Answered by Tutor77028 D. Maths tutor

3418 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I remember the coefficients of a Taylor expansion?


(a) By using a suitable trigonometrical identity, solve the equation tan(2x-π/6)^2 =11-sec(2x-π/6)giving all values of x in radians to two decimal places in the interval 0<=x <=π .


f(x)= 2x^3 -7x^2 + 2x +3. Given that (x-3) is a factor of f(x), express f(x) in a fully factorised form.


What is the amplitude and period of y=3sin(5x)?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences