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There are two points 'A' and 'B' on a graph, their coordinates are (0,1) and (10,6) respectively. 1)Find the equation of the line that runs through both of these points.2)Find the equation of a line perpendicular to this through point 'B'.

Draw a graph to see the question more clearly.1) Find the slope using the rise over run formula. ( m = 1/2 ) Put this slope into the equation of a line formula along with one of the points. ( y = (1/2)*x + 1...
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Answered by Robert T. • Maths tutor
2865 Views

Factorise and solve x^2 -8x=15=0

x=3 or x=5
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Answered by Vineet A. • Maths tutor
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The straight line L1 passes through the points with coordinates (4, 6) and (12, 2) The straight line L2 passes through the origin and has gradient -3. The lines L1 and L2 intersect at point P. Find the coordinates of P.

First, find equations for the 2 lines in the standard cartesian form y=mx+c:L1: To find gradient = dy/dx = change in y/change in x = (y2-y1)/(x2-x1) = (2-6)/(12-4) = -4/8 = -0.5 = m To find intercept use gra...
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Answered by Hugo F. • Maths tutor
5256 Views

find dy/dx= x^2 +x^3

dy/dx= 2x+(1/3)x^2
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Answered by Safa A. • Maths tutor
3566 Views

Differentiate y=3x^4 with respect to x

First we "bring the power down", that is, multiply by the power. Secondly, we subtract 1 from the power.Our answer is then dy/dx = 4*3x^(4-1) = 12x^3
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Answered by Ella B. • Maths tutor
5227 Views