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Factorise x^2+3x+2=0

Using the letters a,b and c we label our coefficients by comparing our equation to ax^2+bx+c=0. This means we have; a=1, b=3 and c=2.To factorise a quadratic equation we need to put it into the form (x+ )(x+...
DA
Answered by Daisy A. Maths tutor
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Factorise x^2+6x-27

Label the three coefficients (each number, including an invisible 1 in from of the x 2 ) as a, b and c.Think of it in two parts: a multiplied by c, which is just -27 in this example.The second part is just t...
BG
Answered by Benjamin G. Maths tutor
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2x + y = 1, x^2 + y^2 = 1

1 : 2x + y = 1 y = 1 - 2x2 : x^2 + (1-2x)^2 = 1 x^2 + (1-2x)(1-2x) = 1 x^2 + 1 - 2x - 2x + 4x^2 = 1 5x^2 - 4x + 1 = 1 5x^2 - 4x = 0 x(5x - 4) = 0 x = 0, x = 4/5 y = 1, y = -3/5
JT
Answered by Josh T. Maths tutor
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Prove that the square of an odd number is always 1 more than a multiple of 4.

Recap, what is 'squaring a number'? Multiplying a number by itself, for example, 3 x 3 = 9. The question hasn't given us a specific number, hence that value can be any number, it is said to be a 'variable'. ...
FO
Answered by Florence O. Maths tutor
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Solve the equation to 2 two decimal places: (2x+3/x-4 ) - (2x-8/2x+1) = 1

(2x+3/x-4 ) - (2x-8/2x+1) = 1 (2x+3/x-4) = 1 + (2x-8/2x+1) [Add (2x-8/2x+1) to each side]2x+3= x-4 + (2x-8)(x-4)/2x+1 Times both sides by (x-4) (2x-1)=(x-4)(2x+1) + (2x-8)(x-4) [Times both sides by (2x+1) - ...
JK
Answered by Jude K. Maths tutor
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