Solve the equation to 2 two decimal places: (2x+3/x-4 ) - (2x-8/2x+1) = 1

 (2x+3/x-4 ) - (2x-8/2x+1) = 1 (2x+3/x-4) = 1 + (2x-8/2x+1) [Add (2x-8/2x+1) to each side]2x+3= x-4 + (2x-8)(x-4)/2x+1 Times both sides by (x-4)(2x-1)=(x-4)(2x+1) + (2x-8)(x-4) [Times both sides by (2x+1) - therefore we have removed the denominators from both sides]
Expand all to give;4x2 + 8x + 3= 2x2 - 7x -4 + 2x2 - 16x - 32 [Collect like terms, and simplify]-25 = -31x0.81 = x [Divide to give x, and round to two decimal places as asked]

JK
Answered by Jude K. Maths tutor

3751 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you calculate the sum of all internal angles of a regular polygon?


Harry mixes white paint and blue paint in the ratio 2:5. He makes a total of 21 litres of paint. How much more blue paint does he need to add to the mixture so that the ratio of white paint to blue paint becomes 1:4?


How do you convert a recurring decimal in to a fraction?


Find the values of k for which the equation (2k-3)x^2- kx+(k-1)=0 has equal roots.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning