Solve the equation to 2 two decimal places: (2x+3/x-4 ) - (2x-8/2x+1) = 1

 (2x+3/x-4 ) - (2x-8/2x+1) = 1 (2x+3/x-4) = 1 + (2x-8/2x+1) [Add (2x-8/2x+1) to each side]2x+3= x-4 + (2x-8)(x-4)/2x+1 Times both sides by (x-4)(2x-1)=(x-4)(2x+1) + (2x-8)(x-4) [Times both sides by (2x+1) - therefore we have removed the denominators from both sides]
Expand all to give;4x2 + 8x + 3= 2x2 - 7x -4 + 2x2 - 16x - 32 [Collect like terms, and simplify]-25 = -31x0.81 = x [Divide to give x, and round to two decimal places as asked]

JK
Answered by Jude K. Maths tutor

3405 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following equation : x^2 + 2x +1 = 0


How to be fully prepared for the exam?


The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a


A circular table has a diameter 140 cm. Calculate the area of the table in cm^2, leaving your answer as a multiple of pi.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning