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√(6^2+8^2)=^3√125a^3

√(6 2 +8 2 )= 3 √125a 3 √36+64=5a√100=5a10=5aa=2
TP
Answered by Thomas P. • Maths tutor
3372 Views

Solve algebraically the simultaneous equations: x^2 + 3x + 10 = y and; 4 - 2x = y. Give answers as co-ordinates.

Where we are given two equations that equal the same thing we can substitute one into the other e.g. (1) x 2 + 3x + 10 = y (2) 4 - 2x = y. Sub (2) into (1) - replace y in (1) for (4 - 2x): x 2 + 3x + 10 = 4 ...
GR
Answered by Georgia R. • Maths tutor
3032 Views

Solve the simultaneous equations 5x+y=21 and x-2y=9

To answer this, you need to try and remove on of the letters from the equation. You could multiply the first equation by 2 so that the number in front of the y's are the same in both equations, with 10x+2y=2...
JW
Answered by Jess W. • Maths tutor
3857 Views

S is a geometric sequence. a) Given that (√x - 1), 1, and (√x + 1) are the first three terms of S, find the value of x. b) Show that the 5th term of S is 7 + 5√2

a) We can get the result by calculating the common ratio between elements 1 and 2, and 2 and 3. R n = 1/√x-1 /Ratio between 1st and 2nd R n = √x + 1 /Ratio between 2nd and 3rd 1/√x-1 = √x + 1 /*(x + 1) 1 = (...
MD
Answered by Marek D. • Maths tutor
12396 Views

5(7x + 8) + 3(2x + b) ≡ ax + 13 Find the values of a and b

35x + 6x + 3b ≡ ax + 13 41x + 3b ≡ ax + 13 when x=0 3b + 40 = 13 3b= -27 b=-9 so 41x - 27 + 40 ≡ ax + 13 when x = 1 41-27 + 40 = a + 13a = 41
TM
Answered by Taylor M. • Maths tutor
6582 Views