Solve the simultaneous equations 5x+y=21 and x-2y=9

To answer this, you need to try and remove on of the letters from the equation. You could multiply the first equation by 2 so that the number in front of the y's are the same in both equations, with 10x+2y=21. Then, if you take the 2ndequation away from the 1st, the y terms will disappear giving you 4x=12. Then, to get x, divide through by 4 for x=3. That’s one half of the answer, now to get y, sub x=4 into one of the equations and rearrange for y. Subbing it into the top one: 5(4) + y = 21 so 20+y=21 and y=1. So, x=4 and y=1.

JW
Answered by Jess W. Maths tutor

3586 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Determine if the Following equality has real roots: (3*X^2) - (2*X) + 4 = (5*X^2) + (3*X) + 9, If the equation has real roots, calculate the roots for this equation.


Factorise the following- A) 4x+12xz. B) 3xy + 6y d) 4A^2B^2+ 8AB^2 +16AB^3


Two simultaneous questions are given as 3x+2y = 9, and x-2y = -5. Find the values for x and y


Find the coordinates where the curve y=x^2+6x+5 crosses the x-axis.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning