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Express 6x^2+4x-1 in the form a(x+b)^2+c

In this case we need to complete the square as follows:6((x+2)^2-4)-1= 6(x+2)^2-24-1= 6(x+2)^2-25where a = 6, b = 2, c = -25
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Answered by Ahmad H. • Maths tutor
4178 Views

A bag contains 4 red counters and some blue counters in the ratio 1:4 respectively. How many counters are there in the bag altogether?

Calculate how many blue counters there are first. 4 divided by 1 = 4.4 multiplied by 4 = 16.16 blue counters in the bag.4 red counters and 16 blue counters makes 20 counters in the bag.
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Answered by EMMA B. • Maths tutor
4050 Views

Given that y = 16x + x^-1, find the two values of x for which dy/dx = 0

Expected layout of answer in an exam: y = 16x + x -1 dy/dx = 16 - x -2 dy/dx = 0 implies that 16 - x -2 = 0this implies that 16 = x -2 16 = 1/x 2 16x 2 = 1x 2 = 1/16therefore x = +/- 1/4x = 1/4, x = -1/4 whe...
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Answered by Sawdah H. • Maths tutor
4448 Views

multiply out (2x-4)(x-2) and simplify.

The method I would use here is FOIL (first outer inner last). A common mistake is not multiplying out all terms, using FOIL will ensure you do this.The working I would expect to see:2x^2-4x-4x+8 (order shows...
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Answered by Ben W. • Maths tutor
4494 Views

Solve the simultaneous equations: 3x+2y=11, 2x-5y=1.

Step 1) Label Equations 1) 3x+2y=11 2) 2x-5y=1 Step 2) Multiply so that one variable has same coefficient in both equations. 1)x5 15x+10y=55 2)x2 4x-10y=2 Step 3) Add/Subtract equations to remove one variabl...
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Answered by Harry B. • Maths tutor
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