Given that y = 16x + x^-1, find the two values of x for which dy/dx = 0
Expected layout of answer in an exam:y = 16x + x-1dy/dx = 16 - x-2dy/dx = 0 implies that 16 - x-2 = 0this implies that 16 = x-216 = 1/x216x2 = 1x2 = 1/16therefore x = +/- 1/4x = 1/4, x = -1/4 when dy/dx = 0
SH
Related Maths A Level answers
All answers ▸A curve has the equation 6x^(3/2) + 5y^2 = 2 (a) By differentiating implicitly, find dy/dx in terms of x and y. (b) Hence, find the gradient of the curve at the point (4, 3).
integrate 1/(x^2+4x+13)
A) Differentiate ln(x) b) integrate ln(x)
If the quadratic equation kx^2+kx+1=0 has no real roots, what values of k are possible?