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Solve the equation (6/x-2)-(6/x+1) =1

1 - Multiply each part of equation by denominators to multiply out the fractions. {(6(x-2))/x-2} - {(6(x-2))/x+1} = 1(x-2). This would simply to 6 - {(6(x-2))/x+1} = x - 2. We then do the same for the other ...
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Answered by Aman K. • Maths tutor
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A is the point with coordinates (2,7) and B is the point with coordinates (8,10). Find the coordinates of the midpoint of AB.

1 - Draw a sketch graph of where the points would be to help visualise the midpoint. 2 - Work out the midpoint for each axis. For example, for x, it would be (0.5*(2+8)) = 5 and for y, it would be (0.5*(7+10...
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Answered by Aman K. • Maths tutor
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(Q20 Non-Calculator paper, Higher Tier) Solve algebraically the simultaneous equations: x^2 + y^2 = 25 and y – 3x = 13

We have a quadratic equation (unknowns are raised to the power of 2) and a liner equation (power 1). We will use the linear equation to express one of the variables, e.g. y , in terms of the other, i.e. x . ...
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Answered by Darena S. • Maths tutor
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A 20-foot ladder is leaning against a vertical wall. The bottom of the ladder is pulled away horizontally from the wall at 3 feet per second. How fast is the top of the ladder sliding down the wall when the bottom of the ladder is 10 feet away?

This question can be divided into two different equations. In order to calculate how fast the ladder is sliding downwards, you need to know at what original vertical height the ladder is leaning on the wall....
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Answered by Maximilian L. • Maths tutor
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How do I find the equation of the normal to the curve y=x^2 at the point (x1,y1)? Where x1=2 and y1=4 .

I would get the student to draw a diagram of the situation.. so draw the curve y=x^2, the tangent at (2,4) and then the normal. Then I would highlight to them that the equation we want is the equation of a s...
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Answered by Mohammad M. • Maths tutor
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