Top answers


Find all solutions of x^2-x-6 using the quadratic formula

From the given quadratic, we have a=1, b=-1, and c=-6. We substitute these values into the quadratic formula, x=-b+-sqrt(b^2-4ac)/2a, giving us x=-1+-sqrt(-1^2-4 1 -6)/2*1. This simplifies to x=1+-5/2. Keepi...
JH
Answered by Jack H. Maths tutor
4406 Views

How can I introduce myself?

For me, my name is Hayley then it will be わたしはヘイリイです。ヘイリイis Hayley in Katakana (used for english phase in japanese).わたしis I am, ですis an ending after a noun/adjective for a japanese present form sentences.
HL
2258 Views

Express square root of 48 in the form n x square root of 3 , where n is an integer

We know that 3 x 16 = 48 This is equivalent to saying 3 x 4^2 = 48 Therefore the square root of 48 can be written as square root of (4^2 x 3) = 4 x square root 3
HW
Answered by Helena W. Maths tutor
10004 Views

A curve has equation y=x^2 + (3k - 4)x + 13 and a line has equation y = 2x + k, where k is constant. Show that the x-coordinate of any point of intersection of the line and curve satisfies the equation: x^2 + 3(k - 2)x + 13 - k = 0

When we deal with points of interception, this immediately indicates that these two equations have to equal. Therefore, begin by equaling these two equations: x^2 + (3k - 4)x + 13 = 2x + k Bring all figures ...
HW
Answered by Helena W. Maths tutor
12568 Views

Solve 5x - 6 = 3x + 7

Rearrange the equation so that both x's are on the same side of the equation, making sure that you change the sign of the number you bring across: 5x - 3x = 7 + 6 Now simplify: 2x = 13 Divide by 2: x = 13/2
HW
Answered by Helena W. Maths tutor
8556 Views