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Find the equation for the tangent to the curve y^3 + x^3 + 3x^2 + 2y + 8 = 0 at the point (2,1)

As the tangent has the same gradient as the curve at the particular point, we need to find the gradient of the curve. To find the gradient we need to differentiate. Due to there being two variables in this e...
AE
Answered by Aphishek E. • Maths tutor
4713 Views

How do I tackle an unseen poem in an exam?

The idea of an unseen poem can be very intimidating, especially when there is a time limit. To analyse an unseen poem begin by reading the poem in order to get a general understanding of the text, and start ...
PR
12140 Views

Why is the left side of the heart bigger than the right side of the heart?

Core: The muscle of the left ventricle is significantly thicker than the muscle of the right ventricle - recall that the ventricles are the chambers which contain the blood before it leaves the heart (as opp...
FD
52597 Views

Find an equation of the straight line that is perpendicular to the straight line x + 3y = 7 and that passes through the point (4,9).

y = 3x - 3
VP
Answered by Vikesh P. • Maths tutor
3778 Views

Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form

x^3=1=e^2(pi) i k x=e^2(pi) i k/3 The three roots are k=0 x=1 k=1 x=e^2(pi)*i/3 k=-1 x=e^-2(pi) i k/3
AA
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