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Prove that an angle subtended by an arc is double at the centre then at the perimeter.

After drawing, bisect the perimeter angle in two from the centre. We now have two isosceles triangles with the sides the same length (1 radius from the centre). We know that 2 angles in each triangle add up ...
MP
Answered by Matthew P. • Maths tutor
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Explain one advantage and one disadvanatge of using temporary staff. (6 marks)

Temporary staff have an employment contract with their employer but it is for a predetermined time period or until a specific task has been completed. One advantage of having temporary employees is that they...
RI
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Outline and evaluate the diathesis-stress model of schizophrenia

The Diathesis Stress model of schizophrenia is part of the interactionist approach that see’s schizophrenia developing due to an interaction between the biological (diathesis) and the environmental (stress) ...
AD
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The complex conjugate of 2-3i is also a root of z^3+pz^2+qz-13p=0. Find a quadratic factor of z^3+pz^2+qz-13p=0 with real coefficients and thus find the real root of the equation.

z-2+3i times z-2-3i = z 2 -4z+13. z 3 -2z 2 +5z+26 divided by z 2 -4z+13 = z+2. Therefore the real root is z=-2.
WN
Answered by William N. • Maths tutor
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Given that 2-3i is a root to the equation z^3+pz^2+qz-13p=0, show that p=-2 and q=5.

Substitute 2-3i into equation using part i (2-3i) 3 =-46-9i. -46-9i+p(-5-12i)+q(2-3i)-13p=0. -46-18p+2q-9i-12pi-3iq=0. Real: -46-18p+2q=0 and Imaginary: -9-12p-3q=0. p=-2, q=5
WN
Answered by William N. • Maths tutor
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