The complex conjugate of 2-3i is also a root of z^3+pz^2+qz-13p=0. Find a quadratic factor of z^3+pz^2+qz-13p=0 with real coefficients and thus find the real root of the equation.

z-2+3i times z-2-3i = z2-4z+13. z3-2z2+5z+26 divided by z2-4z+13 = z+2. Therefore the real root is z=-2.

WN
Answered by William N. Maths tutor

5443 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Let y(x) be a function with derivative y'(x)=x^2-2 and y(0) =7. What is the value of y at x = 3?


Why does ln(x) differentiate to 1/x ?


Find (dy/dx) of x^3 - x + y^3 = 6 + 2y^2 in terms of x and y


Find the exact solution, in its simplest form, to the equation 2ln(2x+1) - 10 = 0.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences