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The curve C has the equation: 16y^3 +9x^2y-54x=0, find the x coordinates of the points on C where dy/dx = 0

C: 16y 3 + 9x 2 y -54x = 0 d/dx(16y 3 ) + d/dx(9x 2 y) + d/dx(-54x) = d/dx(0).............=>48y 2 .dy/dx + 9x 2 .dy/dx + y.18x - 54 = 0 dy/dx(48y 2 +9x 2 ) = 54 - 18xy........................................
EP
Answered by Elliot P. • Maths tutor
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A person swims from a depth of 0.50 m to a depth of 1.70 m below the surface of the sea. density of the sea water = 1030 kg/m^3 gravitational field strength = 9.8 N/kg Calculate the increase in pressure on the swimmer. Give the Unit.

ΔP = Δh ρ g Δh = 1.7 - 0.5 = 1.2 m ρ = 1030 kg/m 3 g = 9.8 N/kg ΔP = 1.2 (m) x 1030 (kg/m 3 ) x 9.8 (N/kg) = 12,112.8 N/m 2 = 12,112.8 Pa
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Answered by Elliot P. • Physics tutor
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‘Germany was treated fairly at Versailles.’ How far do you agree with this statement? Explain your answer.

In history, answers have less to do with the actual content and more to do with how essays are structured. I have therefore given the structure which I would provide to a student at GCSE level and explained ...
HJ
Answered by Henry J. • History tutor
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How do you factorise a quadratic equation?

You should already be familiar with multiplying out brackets to arrive at a quadratic equation, which will look something like the following: (x + 2)(x + 3) = x 2 + 2x + 3x + 6 = x 2 + 5x + 6 Factorising is ...
EM
Answered by Eleanor M. • Maths tutor
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When the current through an ohmic conductor is 2A, the potential difference across it is 6V. What is the potential difference across the same ohmic conductor when the current is increased to 3A?

To answer this, you need to pick up on the clues in the question. "Ohmic conductor" is explicitly mentioned twice, so this is likely to be important. You should know that for ohmic conductors, p.d....
EG
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