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Explain how the human body maintains blood glucose levels within a narrow range

As part of homeostasis, it is vital for the human body to maintain blood glucose levels within a narrow range. The 2 main hormones involved are insulin, when glucose levels are too high, and glucagon, when g...
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Answered by Sally H. • Biology tutor
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Edexcel C1 2015 Q10. A curve with equation y = f (x) passes through the point (4, 9). Given that f′(x)=3x^(1/2)-9/(4x^(1/2))+2. Find f(x), giving each term in its simplest form.

I would go through a similar example of integration with the student using the whiteboard and would explain the use of integration, and would then get them to do the above question, giving them hints when ne...
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Answered by Issy A. • Maths tutor
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Define the term "Gravitational Potential" and write down a formula which defines it.

The Gravitational Potential is the work done in moving a unit mass (1kg) from an infinite distance to a point in a radial gravitational field. The Gravitational Potential is defined as being zero an infinite...
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Answered by Jay B. • Physics tutor
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A gardener uses this formula to work out how much he charges to make a lawn. C = (7(14+A))/3. C is the charge in £, A is the area in m^2. He makes a rectangular lawn measuring 12.5 m by 17.6 m. How much does he charge? [3 marks]

Rectangular Lawn of 12.5 x 17.6m. (Draw Rectangle) Area=Length Height A=12.5 17.6 A=220m^2 Substitute into formula: C=(7(14+A))/3 C=(7(14+220))/3 C=(7(234))/3 C=(1638)/3 C=546 The gardener will charge £546.
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Answered by Joshua F. • Maths tutor
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Factorise f(x) = 6x^3 -7x^2 -x +2 = 0

Try to find first root: f(1) = 6 - 7 -1 + 2 = 0, therefore x-1 is a root. Find quadratic by inspection: (x-1)( )= 6x^3 -7x^2 -x +2 (x-1)(6x^2 - x - 2) Factorise quadratic: (x-1)(2x+1)(3x-2) = 0
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Answered by Tutor40745 D. • Maths tutor
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