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The relative formula mass of CaO is 56 and the relative formula mass of CO2 is 44. What is the mass of CaO that can be obtained from 200 g of CaCO3. CaO3 -> CaO + CO2

We are given the relative formula mass (RFM) of CaO and CO 2 , we should therefore calculate the RFM of CaO 3 : RFM of CaCO 3 = 40 + 12 + (16 x 3) = 100 If we look at the reaction in the question, we can see...
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Answered by Joshua H. • Chemistry tutor
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What is the relative formula mass of CaCO3?

The relative formula mass (RFM) is simply just a sum of the atomic masses that make up the compound in question. Ca = 40 C = 12 O = 16 RFM of CaCO 3 = 40 + 12 + (16 x 3) = 100 Note we have three oxygens so w...
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Answered by Joshua H. • Chemistry tutor
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24 g of Magnesium reacts with 16 g of Oxygen to produce 40 g of magnesium oxide. What mass of magnesium would you need to produce 10 g of magnesium oxide?

There are two ways to work this out, one is a lot simpler than the other, I will post the simpler method here. The relative formula mass of magnesium oxide, MgO (40), is just a sum of the mass of magnesium (...
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Answered by Joshua H. • Chemistry tutor
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0.250 g of a hydrocarbon known to contain carbon, hydrogen and oxygen was subject to complete combustion and produced 0.3664 g of CO2 and 0.1500 g of H2O. What is the empirical formula of this hydrocarbon?

The first step here is to determine the mass of C in CO 2 and the mass of H in H 2 O. This is done by dividing the relative atomic mass, Mr, by the relative molecular mass of the compound, M CO2 or M H2O , a...
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Answered by Joshua H. • Chemistry tutor
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1.5 g of hydrocarbon undergoes complete combustion to give 4.4 g of CO2 and 2.7 g of H2O. Given this data, what is the empirical formula of this hydrocarbon?

The first step here is to determine the mass of C in CO 2 and the mass of H in H 2 O. This is done by dividing the atomic mass by the molecular mass and then multiplying by the mass of compound produced. For...
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Answered by Joshua H. • Chemistry tutor
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