24 g of Magnesium reacts with 16 g of Oxygen to produce 40 g of magnesium oxide. What mass of magnesium would you need to produce 10 g of magnesium oxide?

There are two ways to work this out, one is a lot simpler than the other, I will post the simpler method here.

The relative formula mass of magnesium oxide, MgO (40), is just a sum of the mass of magnesium (24) and the mass of oxygen (16).

24 + 16 = 40

We are told that 24 g of Mg produces 40 g of MgO when it reacts with 16 g of oxygen. We only need 10 g of MgO, 1 quarter of that given in the question.

In order to produce 10 g of MgO, we therefore only need a quarter of what we needed to make 40 g of MgO.

So, we would only need 24 g / 4 = 6 g of Mg to produce 10 g of MgO.

JH
Answered by Joshua H. Chemistry tutor

73522 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

What type of compound is CH3COOH? Circle the correct answer. A) Alkene B) Carboxylic acid C) Alcohol D) Ketone


In what circumstances can an ionic compound conduct electricity? How?


What is the difference between covalent compounds and ionic compounds?


Why does reactivity increase as you go down Group 1 metals?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning