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Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%

C = 12 g/molO = 16 g/molH = 1 g/mol Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O
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Answered by Rachael T. • Chemistry tutor
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What should I expect from an Oxbridge interview?

The approach may vary in different colleges but my own experience was a lot less intimidating than I thought it would be. I was given a poem to analyse before I went in and then the first part of the convers...
JB
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When should I use "tu" and "vous"?

The words “tu” and “vous” both translate to “you” in English. In English, one can use “you” to address any person or number of people whereas in French a distinction is made according to whom one is talking ...
GA
Answered by Gabriella A. • French tutor
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How do I structure an essay?

At GCSE level essays should be structured with a simple Introduction- 3/4 paragraphs- Conclusion structure.Introduction: This should lay out your argument for the essay, and show how you will go about arguin...
BD
Answered by Beatrice D. • English tutor
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how does the chemical structure of amino acids lead to variable physical structures of proteins

Amino acids are made up of an amine group, a carboxyl group, a hydrogen and a variable group (often noted as R) all bound to one Carbon. These amino acids can bind to one another by the amine group and the c...
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Answered by Adam B. • Biology tutor
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