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Part 2: from the empirical formula, calculate the molecular formula if the molecular weight of the substance is 180 g/mol

Molcular weight of CH2O = 30 g/mol 180/30 = 6 Molecular formula = C6H12O6
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Answered by Rachael T. • Chemistry tutor
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Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%

C = 12 g/molO = 16 g/molH = 1 g/mol Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O
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Answered by Rachael T. • Chemistry tutor
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What should I expect from an Oxbridge interview?

The approach may vary in different colleges but my own experience was a lot less intimidating than I thought it would be. I was given a poem to analyse before I went in and then the first part of the convers...
JB
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When should I use "tu" and "vous"?

The words “tu” and “vous” both translate to “you” in English. In English, one can use “you” to address any person or number of people whereas in French a distinction is made according to whom one is talking ...
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Answered by Gabriella A. • French tutor
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How do I structure an essay?

At GCSE level essays should be structured with a simple Introduction- 3/4 paragraphs- Conclusion structure.Introduction: This should lay out your argument for the essay, and show how you will go about arguin...
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Answered by Beatrice D. • English tutor
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