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Bismuth-208, which has an atomic mass of 208u and 83 protons in the nucleus, decays through the emission of 2 alpha particles and a beta-positive particle. What isotope results from this decay?

208 83 Bi ==> x y Z + 4 2 a + 4 2 a + 0 1 B x = 208 - 8 = 200 y = 83 - 5 = 78 Proton number = 78 therefore Z = Pt Z= 200 78 Pt
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Answered by Danny L. • Physics tutor
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During the redox reaction in glycolysis, which molecule acts as the oxidising agent?

The oxidation of glyceraldehyde 3-phosphate (G3P), a three-carbon sugar, yields energy. In this oxidation, electrons and H+ are transferred to NAD+, forming NADH, and a phosphate group is attached to the oxi...
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Answered by Daniel A. • Biology tutor
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Why is internal temperature regulation an important homeostasis?

Internal temperature of your body must be tighly controlled. The key processes of your body are driven by enzymatic activity and there is an optimal temperature at which these operate. If body temperature in...
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Answered by Archie I. • Biology tutor
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Factorise and solve x2 - 8x + 15 = 0.

Factorise and solve x 2 - 8x + 15 = 0. When factorising there are 3 things to look for; A common factor in each component of the equation. In this case there are no common factors. Whether the equation is ma...
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Answered by Olivia R. • Maths tutor
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Using standard formulae, derive an expression for the final speed of a falling object in terms of its change in height. Assume zero air resistance or other resistive forces.

E k = (1/2)mv 2 E p = mg(dh) Set these equal to each other, because of conservation of energy: (1/2)mv 2 = mg(dh) Cancel the mass: (1/2)v 2 = g(dh) v 2 = 2g(dh) v = (2g(dh)) 1/2
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Answered by Danny L. • Physics tutor
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